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2^(3x+5)=(1/2048)
We move all terms to the left:
2^(3x+5)-((1/2048))=0
We add all the numbers together, and all the variables
2^(3x+5)-((+1/2048))=0
We multiply all the terms by the denominator
(2^(3x+5))*2048))-((+1=0
We move all terms containing x to the left, all other terms to the right
(2^(3x+5))*2048))-((=-1
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